Crosses the trend line joining

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If m4 is less than 61.8% of m3, then the possibility of m1 initiating any pattern is almost zero. Consequently, we place the ta at the end of m1. Besides: If the ":F3" option is confirmed, m1 starts an elongated plane. If m1 is longer than m(-1) and m(-3), and m2 crosses the trend line joining the lows of m(-2) and m0 in a time period equal to or less than that of m1, then m1 may be the fifth wave of an elongated fifth pattern, and we addto its structure list. If m0 takes less time than m(-1) and m1, then we remove ":s5" from the structure list. If the final level of m1 is exceeded during the formation of m2, then we add x in front of  5. If none of the above conditions fit the market situation, then we put ":F3/:c3 /:sL3/:s5" at the end of m1.

Besides: If m1 is longer than m(-1) and m(-3), and m2  the minimums of m(-2) and m0 in a time period equal to or less than that of m1, then we addto your structure list. If m1 is less than 61.8% of m(-1) and/or the time of m0 is less than that of m(-1) and m1, then we remove the tag ":s5" from the structure list. If m4 is less than 61.8% of m3, we remove. If the  Belize Mobile Number List end point of m1 was exceeded during the formation of m2, then we add x in front of  Let's look at condition (b) of rule 4 in the example. LiteFinance: Part 6, Modification of Glenn Neely's NeoWave Wave Theory |  Litefinance Wave m2 is between 61.8% and 100% of m1. It means that the requirements of rule 4 are met. LiteFinance: Part 6, Modification of Glenn Neely's NeoWave Wave Theory |  Litefinance The length of m0 is 61.8% of m1.



Then the requirements of condition (b) are met. LiteFinance: Part 6, Modification of Glenn Neely's NeoWave Wave Theory |  Litefinance Now let's define the appropriate category. The m3 amplitude is from 100% to 161.8% of m2. So, in our case category i of condition (b) of rule 4 applies. LiteFinance: Part 6, Modification of Glenn Neely's NeoWave Wave Theory |  Litefinance The initial point of m3 (pink horizontal line on the graph) is reached in a time less than or equal to the time it took to form. Since it is difficult to compare the period in this case with the naked eye, I marked the period of m3 with a red area and the period of m2 with a green area. It means that point 1 applies to our example. Therefore, m1 could hardly be the final segment of any Elliott pattern. So, we putat the end of m1.